How to resolve could not launch Error in Url launcher

Question

I am trying open a link on Google pixel API 30 Emulator but keep on getting error. Have tried flutter clean, restarted app.

Dependency:-

url_launcher: ^6.0.3

Code:-

  InkWell(
onTap:() => _launchURL("https://google.com"),
child: Image.asset("assets/images/googleIcon.jpg")
),

_launchURL(String url) async {
if (await canLaunch(url)) {
  await launch(url);
} else {
  throw 'Could not launch $url';
}

}

Error:-

   Unhandled Exception: Could not launch https://google.com

Done, Thanks to this:- https://stackoverflow.com/questions/63625023/flutter-url-launcher-unhandled-exception-could-not-launch-youtube-url-caused-b/65082750 — GAGAN SINGH, May 27 '21 at 07:19
Have a look at this answer: https://stackoverflow.com/a/68611830/6666348 — Kamran Taghaddos, Oct 25 '22 at 13:57

score 0 · Answer 1 · answered May 27 '21 at 07:20

Add a URI class since url_launcher recommends encoding the URLs as URI. Link to Doc

final Uri _faireGitHubUri = Uri.https('google.com', '/');

    InkWell(
onTap:() => _launchURL(_websiteUri.toString()),
child: Image.asset("assets/images/googleIcon.jpg")
),

How to resolve could not launch Error in Url launcher

1 Answers1