OOP theory question :: $this->someVariable = $someValue

Question

I was wondering what this statement actually does:

$this->nameInObject = $someValue;

So if you're inside a class object that has a variable "nameInObject", are you assigning a value of someValue to that instance of nameInObject? Is it only intended to last as long as the session? Does it over ride the initial value of nameInObject?

Thanks

score 2 · Accepted Answer · answered Jul 21 '11 at 02:43

2

It will override any previous value.

It will only affect the current instance of the object.

answered Jul 21 '11 at 02:43

alex

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score 1 · Answer 2 · answered Jul 21 '11 at 02:48

Yes, you are assigning the value of someValue to the instance of nameInObject.

Yes, nameInObject will last only the lifetime of the variable this refers to; however, someValue will continue to live on.

Yes, you will override whatever value nameInObject contains with the value someValue contains.

OOP theory question :: $this->someVariable = $someValue

2 Answers2