Java JOptionPane default text

Question

When I ask a user to enter a quantity for a program I have made using the code below, the default text is 3.

String input = JOptionPane.showInputDialog(null, "Please enter new quantity",
                                           JOptionPane.QUESTION_MESSAGE);

How do I change this?

What do you mean by "the default text"? – Eng.Fouad Jul 20 '11 at 13:47 — Eng.Fouad, Jul 20 '11 at 13:47
The text in the text field which is already entered – Harry Martland Jul 20 '11 at 13:49 — Harry Martland, Jul 20 '11 at 13:49

Harry Joy · Accepted Answer · 2011-07-20T13:56:26.680

19

The method you have used is:

public static String showInputDialog(Component parentComponent,
                                     Object message,
                                     Object initialSelectionValue)

Here 3rd argument (initialSelectionValue) is default value in text field. You gave JOptionPane.QUESTION_MESSAGE as 3rd argument which is an int constant having value = 3. So you get 3 as a default value entered in text field.

Try this:

String input = JOptionPane.showInputDialog(null,
                "Please enter new quantity", "");

or this

String input = JOptionPane.showInputDialog(null,
                "Please enter new quantity", "Please enter new quantity",
                JOptionPane.QUESTION_MESSAGE);

edited Jul 20 '11 at 13:56

answered Jul 20 '11 at 13:51

Harry Joy

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6

`String input = JOptionPane.showInputDialog(null, "Please enter new quantity", "Please enter new quantity", JOptionPane.QUESTION_MESSAGE,null,null,"default text").toString;` – Neifen Sep 28 '11 at 07:54
1

^^ I think that should be voted as the best answer to this question as it allows for a title also .But for some reason it gives me an error. – Hele Aug 05 '13 at 09:42
2

The reason for NullPointer exception is that you are using `toString()` on the resulting object of `JOptionPane`. You first need to check that the object is not null, and then use `toString()` after. @Neifen 's comment will have null pointer exception if the entry in the input dialog is blank. – user3735633 Jun 29 '15 at 17:47

score 11 · Answer 2 · edited Dec 08 '13 at 10:32

11

This way it will work:

String input = (String)JOptionPane.showInputDialog(null, "Please enter new quantity",
"Please enter new quantity", JOptionPane.QUESTION_MESSAGE,null,null,"default text");

edited Dec 08 '13 at 10:32

Robert Seifert

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answered Dec 08 '13 at 10:14

Tomás Marques

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Jeffrey · Answer 3 · 2011-07-20T13:57:32.053

0

The method you are using is JOptionPane.showInputDialog(Component, Object, Object).

The method you want to use is JOptionPane.showInputDialog(Component, Object, String, int).

edited Jul 20 '11 at 13:57

answered Jul 20 '11 at 13:48

Jeffrey

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I want the user to be able to enter a number when I did this JOptionPane.showInputDialog(null, "Please enter new quantity", "Please enter new quantity", 1) It just displayed a pop up with no input box, am I doing something wrong??? – Harry Martland Jul 20 '11 at 13:53
@Ste T You will be able to. Change your method call to `String input = JOptionPane.showInputDialog(null, "Please enter new quantity", "Title", JOptionPane.QUESTION_MESSAGE)`; – Jeffrey Jul 20 '11 at 13:55
Please check your links as they appear in the 'preview' in future, and note that it is best to link to the JavaDocs of the current version (adding '6' to the search for `ClassName+javadoc+6` should do it). – Andrew Thompson Jul 20 '11 at 13:56

Java JOptionPane default text

3 Answers3