Graph in Latex using Tikz and PGFplots

Question

How to draw this graph in LaTeX? I have used TikZ but I can't get it done exactly.

A graph to be drawn in Latex

This is what I have tried so far:

\begin{tikzpicture}
   \tkzInit[xmax=6,ymax=6,xmin=-6,ymin=-1]
   \tkzAxeXY
   \draw[thick] (6,3) -- (-4,5);
   \filldraw[black] (6,3) circle (2pt) node[anchor=west] {A(6,3)};
   \filldraw[black] (-4,5) circle (2pt) node[anchor=east] {B(-4,5)};  
\end{tikzpicture}

Output Pic

You should modify your question, not posting your attempts as an answer. — Eddymage, May 19 '21 at 07:26
Where did the output pic come from? It does not really match the code. Also, which library are you using (commands tkzInit, tkzAxeXY...)? — jf_, May 19 '21 at 09:03

score 1 · Answer 1 · answered May 19 '21 at 22:29

Using regular pgfplots you could do the following: Draw the line with the points you choose and label them with nodes. Then draw the additional distance markers using \draw in the axis coordinate system (The concrete positions of all elements may have to be adjusted).

\documentclass{article}

\usepackage{tikz}
\usepackage{pgfplots}
\begin{document}

\begin{tikzpicture}
\tiny
    \begin{axis}[
        width  = 6cm,
        height = 4cm,
        ymajorgrids = true,
        ymin=-1,
        ymax=7,
        xmin=-6,
        xmax=6,
        xtick distance=1,
        ytick distance=1,
        axis y line*=center,
        axis x line*=center,        
        enlarge x limits=.12
    ]
\addplot+[sharp plot] coordinates {(6,3) (1,4) (-4,5) } node[below=1mm, pos=0] {A(6,3)}
    node[pos=0.45,below=1mm] {P(x,y)}
    node[pos=1,below=1mm] {B(-4,5)};

\draw[|-|] (axis cs:1.2,5) -- node [above, rotate=-10] {m=13} (axis cs:6.3,3.9);   
\draw[|-|] (axis cs:-3.8,6) -- node [above, rotate=-10, pos=.3] {n=2} (axis cs:1.2,5);   
   
\end{axis}
\end{tikzpicture}

\end{document}

Output:

Graph in Latex using Tikz and PGFplots

1 Answers1