In bash scripting the loop must continue until the specific keyword is typed

Question

#!/bin/bash
echo "------------"
echo "Welcome Page"
echo "------------"
a="mango"
while true
do
echo "Type mango for exit"
read data
if [ $data -ne $a]; then
echo "Wrong choice"
exit 1
fi

done

The output is:

------------
Welcome Page
------------
Type mango for exit
mango
while.sh: line 10: [: missing `]'
Type mango for exit

paste your script at https://shellcheck.net for validation. – Jetchisel May 13 '21 at 20:35 — Jetchisel, May 13 '21 at 20:35

thirdeye · Answer 1 · 2021-05-15T08:42:35.223

2

It's always good to put quotes around string variables to avoid spaces/newline conflicts.

#!/bin/bash

echo "------------"
echo "Welcome Page"
echo "------------"
a="mango"
while true
do
    echo "Type mango for exit"
    read data
    echo $data
    if [ "$data" != "$a" ]; then
        echo "Wrong choice"
        exit 1
    fi
done

edited May 15 '21 at 08:42

answered May 14 '21 at 06:13

thirdeye

150
7

According to the required logic it should be `[ "$data" == "$a" ] && break || echo "Wrong, try again"` – Abelisto May 15 '21 at 03:35
i think program must exit but not break in case of loops. – thirdeye May 15 '21 at 10:17

In bash scripting the loop must continue until the specific keyword is typed

1 Answers1