run $.ajax() when end typed with format specified. how is it?

Question

i want, when user typed, 0000/00/00(it is format date) after the end of typing run anything(example: AJAX CALL), how is it?

like:
if user typed: 2011/05/04 -> run: $.ajax()...
if user typed: 2011/05 -> not run: $.ajax()...
...

only thing for run $.ajax() is true type this format 0000/00/00.
I hope you understand my purpose.
With respect.

After he types it where? – Alex Turpin Jul 19 '11 at 15:56 — Alex Turpin, Jul 19 '11 at 15:56

score 3 · Accepted Answer · answered Jul 19 '11 at 15:59

3

HTML:

<input type="text" name="datefield" onchange="validateField(this)" />

JS:

function validateField() {
   var val = this.value;
   if (val.length < 10) {
      return;
   }
   if (!val.match(/\d\d\d\d\/\d\d\/\d\d/)) {
      return;
   }
   ... do ajax call here
}

answered Jul 19 '11 at 15:59

Marc B

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You have to be careful cause this will match "blah blah 2011/02/04" as well. You would need to do /^\d\d\d\d\/\d\d\/\d\d$/ if the only thing allowed in there is the date. – Bill Criswell Jul 19 '11 at 16:09
True enough, just a quick/dirty example. – Marc B Jul 19 '11 at 16:11

score 1 · Answer 2 · answered Jul 19 '11 at 16:04

1

$("inputTextBoxSelector").keyup(function(e){
  if($(this).val().match(/\d\d\d\d\/\d\d\/\d\d/){
    $.ajax(....);
    return false;
  }
})

answered Jul 19 '11 at 16:04

ShankarSangoli

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score 0 · Answer 3 · answered Jul 19 '11 at 16:08

0

You can do...

$('input').change(function(e) {
  var val = $(this).val();
  if ( val.length == 10 ) {
    if( val.match(/^\d{4}\/\d{2}\/\d{2}$/) ) {
      $.ajax();
    }
  }
});

You can also try keyup instead of change.

answered Jul 19 '11 at 16:08

Bill Criswell

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run $.ajax() when end typed with format specified. how is it?

3 Answers3