How to remove elements below a number in a list of lists using lambda? Python

Question

If the values within each list are less than or equal to 2 remove them.

What I have tried:

check = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
output = list(filter(lambda x: x[0] <= 2, check))
return (output)

[[3], [4, 5, 6], [7, 8, 9]]

Do you *need* to use `lambda` and `filter` to do this? Did you try using list comprehensions and named functions? — Karl Knechtel, Apr 29 '21 at 23:16

score 3 · Answer 1 · answered Apr 29 '21 at 23:16

3

This is a way without using lambda:

output = [[y for y in x if y>2] for x in check]

answered Apr 29 '21 at 23:16

GabrielP

score 2 · Answer 2 · answered Apr 29 '21 at 23:13

2

What you want is a map to iterate to every list than you apply the filter function.

check = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

output = list(map(lambda x: list(filter(lambda y: y > 2,x)), check))
print(output)

[[3], [4, 5, 6], [7, 8, 9]]

answered Apr 29 '21 at 23:13

DevScheffer

2 Answers2