How to define a Structuremap named instance in Code

Question

I want to create a Structuremap named instance in code, without config file

I want to be able to create the instance like this:

var namedInjector = ObjectFactory.GetNamedInstance<IInjectable>("Other");

I cant define such a type in code. I have found this sample but it uses the old syntax of a previous version and defines the named instance as:

.ForRequestedType<MementoType>()
.AddConcreteType<ConcreteType>(instanceName)

In the latest structuremap version there is no .AddConcreteType(instanceName) method which takes a instance name.

score 19 · Accepted Answer · answered Mar 22 '09 at 20:21

I believe you need something like:

class MyRegistry : Registry {
    public MyRegistry() {
        this.ForRequestedType<IFoo>()
            .TheDefaultIsConcreteType<Bar>()
            .AddInstances( x => {
                x.OfConcreteType<Blap>().WithName("abc");
            });
    }
}
...
ObjectFactory.Configure(x=>x.AddRegistry<MyRegistry>());
IFoo test1 = ObjectFactory.GetInstance<IFoo>(); // Bar
IFoo test2 = ObjectFactory.GetNamedInstance<IFoo>("abc"); // Blap
...
interface IFoo {}
public class Bar : IFoo {}
public class Blap : IFoo {}

Any idea on the new syntax for StructureMap on how to do this? — runxc1 Bret Ferrier, Feb 01 '12 at 17:58

score 1 · Answer 2 · answered Sep 12 '13 at 08:16

1

In the words of new syntax:

            For<IEncryptionService>()
                .AddInstances(x => { x.OfConcreteType<AdvancedEncryptionService>().Named("Advanced"); })
                .Use<EncryptionService>();

answered Sep 12 '13 at 08:16

Sessiz Saat

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How to define a Structuremap named instance in Code

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