Problem with calling a function via a function pointer

Question

I have a struct with a function pointer, that is intended for pointing to the bar() function, but i have no clue how to call the function that's being pointed on:

#include <stdlib.h>
typedef struct Foo
{
  int (*func_ptr)(const char *, const char *);
} Foo;

int bar(const char *a, const char *b)
{
  return 3;
}

int main(void)
{
  Foo *foo = (Foo *)malloc(sizeof(Foo));
  foo->func_ptr = &bar;
  //how do i call the function?
  return 0;
}

Read [*Modern C*](https://modernc.gforge.inria.fr/) and see [this C reference website](https://en.cppreference.com/w/c) — Basile Starynkevitch, Apr 16 '21 at 11:45

score 1 · Accepted Answer · edited Apr 16 '21 at 13:39

1

Imagine your const char *a is "hello" and const char *b is "there", then you can use any of the following forms to call the function by its pointer:

  (foo->func_ptr)("hello", "there");
  (*foo->func_ptr)("hello", "there");
  foo->func_ptr("hello", "there");

edited Apr 16 '21 at 13:39

Eric Postpischil

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answered Apr 16 '21 at 11:51

AKL

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Problem with calling a function via a function pointer

1 Answers1