Is there a way to instantiate the template to accept any random order of param types, other than having to manually include code for every possibility?
You cannot do this for explicit instantiation definitions without macros, but you could use a separate approach and rely on implicit instantiations instead, using SFINAE to restrict the primary template (whose definition you move to the header file) based on two custom traits.
To begin with, given the following type sequence
template <class... Ts>
struct seq {};
we want to construct a trait that, for a given type sequence seq<T1, T2, ...>
(your "10 parameter types"), denoted as s
:
s
shall be a subset of set of types of your choosing seq<AllowedType1, ...>
, and
s
shall contain only unique types.
We can implement the former as:
#include <type_traits>
template <class T, typename... Others>
constexpr bool is_same_as_any_v{(std::is_same_v<T, Others> || ...)};
template <typename, typename> struct is_subset_of;
template <typename... Ts, typename... Us>
struct is_subset_of<seq<Ts...>, seq<Us...>> {
static constexpr bool value{(is_same_as_any_v<Ts, Us...> && ...)};
};
template <typename T, typename U>
constexpr bool is_subset_of_v{is_subset_of<T, U>::value};
and the latter as
template <typename...> struct args_are_unique;
template <typename T> struct args_are_unique<T> {
static constexpr bool value{true};
};
template <typename T, typename... Ts> struct args_are_unique<seq<T, Ts...>> {
static constexpr bool value{!is_same_as_any_v<T, Ts...> &&
args_are_unique<seq<Ts...>>::value};
};
template <typename... Ts>
constexpr bool args_are_unique_v{args_are_unique<Ts...>::value};
after which we can define the primary template as
namespace foo {
namespace detail {
using MyAllowedTypeSeq = seq<int, long, std::string>; // ...
} // namespace detail
template <
typename T, typename U, typename V, typename Seq = seq<T, U, V>,
typename = std::enable_if_t<is_subset_of_v<Seq, detail::MyAllowedTypeSeq> &&
args_are_unique_v<Seq>>>
void doStuff(const T ¶m_a, const U ¶m_b, const V ¶m_c) {
// do lots of stuff
}
} // namespace foo
and where we may and may not use the primary template overload as follows:
int main() {
std::string s{"foo"};
int i{42};
long l{84};
foo::doStuff(s, i, l); // OK
foo::doStuff(s, l, i); // OK
foo::doStuff(l, i, s); // OK
foo::doStuff(l, s, i); // OK
// uniqueness
foo::doStuff(l, l, i); // Error: candidate template ignored
// wrong type
unsigned int ui{13};
foo::doStuff(s, ui, l); // Error: candidate template ignored
}
If types need not actually be unique (it's somewhat unclear from the question) you can simply SFINAE-constrain the primary template only on the first is_subset_of_v
trait:
template <
typename T, typename U, typename V, typename Seq = seq<T, U, V>,
typename = std::enable_if_t<is_subset_of_v<Seq, detail::MyAllowedTypeSeq>>>
void do(const T ¶m_a, const U ¶m_b, const V ¶m_c) {
// do lots of stuff
}