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The ecliptic curve E1: y^2 = x^3+7 over F17 with the base point G is (15, 13) and the second ecliptic curve E2: y^2 = x^3+7 over F31 with the same base point G is (15, 13).

My question is: is there any way to calculate the equivalent point of F31 based on F17? For example: with 7G = (10, 15) of curve F17, how to calculate 7G of F31 ? The result should be 7G = (12, 14) on F31.

Below is all points of two curves:

#----Curve F17-------#

  • 1G = (15, 13)
  • 2G = (2, 10)
  • 3G = (8, 3)
  • 4G = (12, 1)
  • 5G = (6, 6)
  • 6G = (5, 8)
  • 7G = (10, 15)
  • 8G = (1, 12)
  • 9G = (3, 0)
  • 10G = (1, 5)
  • 11G = (10, 2)
  • 12G = (5, 9)
  • 13G = (6, 11)
  • 14G = (12, 16)
  • 15G = (8, 14)
  • 16G = (2, 7)
  • 17G = (15, 4)

#----Curve F31-------#

  • 1G = (15, 13)
  • 2G = (29, 17)
  • 3G = (1, 22)
  • 4G = (20, 19)
  • 5G = (21, 17)
  • 6G = (23, 23)
  • 7G = (12, 14)
  • 8G = (11, 27)
  • 9G = (25, 22)
  • 10G = (7, 19)
  • 11G = (27, 27)
  • 12G = (5, 9)
  • 13G = (0, 24)
  • 14G = (4, 12)
  • 15G = (22, 23)
  • 16G = (3, 13)
  • 17G = (13, 18)
  • 18G = (17, 23)
  • 19G = (24, 4)
  • 20G = (24, 27)
  • 21G = (17, 8)
  • 22G = (13, 13)
  • 23G = (3, 18)
  • 24G = (22, 8)
  • 25G = (4, 19)
  • 26G = (0, 7)
  • 27G = (5, 22)
  • 28G = (27, 4)
  • 29G = (7, 12)
  • 30G = (25, 9)
  • 31G = (11, 4)
Roland
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    This question would be a better match for https://crypto.stackexchange.com/ . – Jim Lewis Apr 13 '21 at 04:59
  • The second basepoint seems wrong. One has isomorphic to Z/18 the other one Z/21. How do you expect this? – kelalaka Apr 13 '21 at 09:22
  • Thank you Jim. I moved my question to this url: https://crypto.stackexchange.com/questions/89362/is-there-any-way-to-mapping-point-between-2-ecliptic-curves but i don't know how to delete this question. – Roland Apr 13 '21 at 09:26

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