So basically, in my bison file if yyparse fails (i.e there is syntax error) I want to print 'ERROR' statement and not print anything else that I do in the above part of bison file in fac the stmt part. if yyparse returns 1 is there any way to skip the content of middle part of bison file? such as idk maybe writing if statement above the stmt part etc? I would appreciate any help! Thanks in advance.
Such as :
%{
#include "header.h"
#include <stdio.h>
void yyerror (const char *s)
{}
extern int line;
%}
%token ...///
%// some tokens types etc...
%union
{
St class;
int value;
char* str;
int line_num;
float float_value;
}
%start prog
%%
prog: '[' stmtlst ']'
;
stmtlst: stmtlst stmt |
;
stmt: setStmt | if | print | unaryOperation | expr
{
if ($1.type==flt && $1.line_num!=0) {
printf("Result of expression on %d is (",$1.line_num);
printf( "%0.1f)\n", $1.float_value);
$$.type=flt;
}
else if ($1.type==integer && $1.line_num!=0){
$$.type=integer;
printf("Result of expression on %d is (%d)\n",$1.line_num,$1.value);
}
else if ($1.type==string && $1.line_num!=0) {
$$.type=string;
printf("Result of expression on %d is (%s)\n",$1.line_num,$1.str);
}
else if ($1.type==mismatch && $1.line_num!=0)
{
$$.type=mismatch;
printf("Type mismatch on %d \n",$1.line_num);
}
else{ }
}
%%
int main ()
{
if (yyparse()) {
// if parse error happens only print this printf and not above stmt part
printf("ERROR\n");
return 1;
}
else {
// successful parsing
return 0;
}
}