Why do i keep getting break error? I have the same problem with continue and pass

Question

from webbot import Browser
import time
import pyautogui
from pyautogui import *
web = Browser()
a == True
web.go_to('http://au.yahoo.com//')
web.scrolly(100)
if a == True:
    try:
        web.click('Skip for now')
        break
web.click('Mail')
time.sleep(10)
pyautogui.keyDown('ctrl')

break keeps coming up with unexpected error

I want it to try click 'skip for now', if not then continue the code

Look up how to properly use `try`. (Hint: what should the program do if the code in the `try` fails?) — Scott Hunter, Apr 11 '21 at 11:34
break is meant to break free of a loop. As there is no loop here break doesn't work and so brings error. If you want your program to continue just don't put a break. And when you call for a try you should mention exception so as mentioned below write at least except : pass — Apo, Apr 11 '21 at 11:35

Diogo · Accepted Answer · 2021-04-11T11:39:02.887

1

try:
    web.click("Skip for now")
except:
    pass

edited Apr 11 '21 at 11:39

answered Apr 11 '21 at 11:34

Diogo

101
3

when i run it an error comes up saying break is outside loop – Cam Butcher Apr 11 '21 at 11:37
forget the break ! – Apo Apr 11 '21 at 11:39

score -1 · Answer 2 · answered Apr 11 '21 at 11:41

-1

web = Browser()
a == True
web.go_to('http://au.yahoo.com//')
web.scrolly(100)
if a == True:
    try:
        web.click('Skip for now')
    except:
        pass
web.click('Mail')
time.sleep(10)
pyautogui.keyDown('ctrl')

EDIT : miss spell of except

answered Apr 11 '21 at 11:41

Apo

338
1
9

Why do i keep getting break error? I have the same problem with continue and pass

2 Answers2