How to mock a method that takes a property expression ie Expression>

Asked Apr 10 '21 at 18:57

Active Apr 10 '21 at 18:57

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I'm trying to mock out a repository method with the signature:

Task<Model> FindByIdAsync<TProperty>(Guid id, Expression<Func<Model, TProperty>> include);

(The include expression is used to include a dependent object on the queried object)

I don't care what the property expression is so I'm trying to use It.IsAny<something> but I can't find the right format for the something

I've got as far as:

mockRepo.Setup(p => p.FindByIdAsync<object>( mockCall.Id, It.IsAny<Expression<Func<Call, object>>>() )).ReturnsAsync(mockObj);

but that doesn't match my code which looks like:

var m = await _modelRepo.FindByIdAsync( someId, m => m.SomePropertyToInclude );

What is the correct way to mock out this method?

asked Apr 10 '21 at 18:57

Ben

1

Have you tried: `It.IsAny>()` or `It.IsAny>()`? – pinkfloydx33 Apr 10 '21 at 20:13
There's also this dunno if it helps: https://stackoverflow.com/a/61322568/491907 – pinkfloydx33 Apr 10 '21 at 20:16
@pinkfloydx33 Thanks for pointing me in the right direction! `p.FindByIdAsync( mockObj.Id, It.IsAny>>() )).ReturnsAsync(mockObj);` worked perfectly. – Ben Apr 10 '21 at 22:04
no prob! `It.IsAnyType` is a *relatively* new thing. I only learned of it recently but it's been around for two years – pinkfloydx33 Apr 10 '21 at 22:13
@pinkfloydx33 please write up an answer and I'll accept it – Ben Apr 11 '21 at 23:57

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