how do I get the first letter of every lines from the text file in mrjob mapper in Python?

Asked Apr 10 '21 at 16:06

Active Apr 10 '21 at 16:06

Viewed 133 times

I am new with the python, I am trying to get the first letter of every lines from the text file in Mrjob , below is my code:

def mapper(self, key, value):
    numCharacters = len(value.strip().replace(" ",""))
    numWords = len(value.strip().split())
        for word in value.strip().split():
            yield value[0],(numCharacters,numWords)

the text.txt file is :

      I want to Remove all white      spaces.   
      new lines  and tabs.   
      not the whitespace.

When i execute : python text.py text.txt , the return of the first letter is the whitespace, not the first letter

" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     4.0
" "     5.67
" "     5.67
" "     5.67

This support to be :

"I"     4.0
"I"     4.0
"I"     4.0
"I"     4.0
"I"     4.0
"I"     4.0
"I"     4.0
"n"     4.0
"n"     4.0
"n"     4.0
"n"     4.0
"n"     5.67
"n"     5.67
"n"     5.67

What is wrong with my code ? please help me to shed the light . Thanks

asked Apr 10 '21 at 16:06

Jen Fisherman

1

Instead of value[0] do value.strip()[0] – lllrnr101 Apr 10 '21 at 16:13
Thank you very much . It works . I thought strip() in loop will remove the whitespace. Neverthought I have to strip one more time. – Jen Fisherman Apr 10 '21 at 16:39
the result say : index error : string index out of range . – Jen Fisherman Apr 10 '21 at 16:53

how do I get the first letter of every lines from the text file in mrjob mapper in Python?

0 Answers0