Virtual assistant python

Question

Hello everyone I am trying to develop a virtual assistant which will help me with some projects so I am trying to get the basics for the final project however I get an error (UnboundLocalError: local variable 'command' referenced before assignment) and I tried to change return command to under the printf(command) but it does not let me talk and a message NONE and the other error which is (TypeError: argument of type 'NoneType' is not iterable) appears on the terminal. So how can I make this work without stop?

CODE BELOW:

import pyttsx3
import pywhatkit
import datetime

listener = sr.Recognizer()
engine = pyttsx3.init()

def talk(text):
    engine.say(text)
    engine.runAndWait()

def take_command():
    try:
        with sr.Microphone() as source:
            print('listening...')
            voice = listener.listen(source)
            command = listener.recognize_google(voice)
            command = command.lower()
            if 'skor' in command:
                command = command.replace ('skor', '')
                print(command)
    except:
        pass
    return command
def run_skor():
    command = take_command()
    print(command)
    if 'play on youtube' in command:
        song = command.replace ('play on youtube', '')
        talk('playing' + song)
        pywhatkit.playonyt(song)
    elif 'search on google' in command:
        sea = command.replace ('search on google', '')
        talk ('searching' + sea)
        pywhatkit.search(sea)
    elif 'tell me the time' in command:
        time = datetime.datetime.now().strftime('%H:%M')
        print(time)
        talk('Current time is' + time)
while True:
    run_skor()```

Add `command=None` as first line of `take_command` or move `return` clause into `try` block. Now your command variable is not defined outside of try block if exception occurs. If you put `return` into try block, then function will return it on success or return None in case of exception (as no return clause will be reached). — STerliakov, Apr 07 '21 at 14:19
you mean ```command=none``` below def right?I did that and it only gives me none and (TypeError: argument of type 'NoneType' is not iterable), also tried to move ```return``` into try but a new error happens (TypeError: argument of type 'NoneType' is not iterable) — Guilherme Candido, Apr 07 '21 at 14:27

score 0 · Answer 1 · answered Apr 07 '21 at 14:24

0

The only change you need to make is in the take_command() function. This is my version of it:

def take_command():
    try:
        with sr.Microphone() as source:
            print('listening...')
            voice = listener.listen(source)
            command = listener.recognize_google(voice)
            command = command.lower()
            if 'skor' in command:
                command = command.replace ('skor', '')
                print(command)
    except sr.UnknownValueError:
        command = ""
    return command

Basically, you can first change the execpt command, to be more specific. sr has a built in command called UnknownValueError. We can use this to be more specific as to when the except command should work. Then, in except, set command to "". This will stop the errors, because when command is returned, it still is a string, and will still work.

answered Apr 07 '21 at 14:24

The Pilot Dude

2,091
2
6
24

It worked mate thank you so much, however what happened is the increase of delay when I talk i mean it takes like 15 seconds to the code get the voice command which didnt hapen before – Guilherme Candido Apr 07 '21 at 14:39
Mmmmm that's weird. Well, that doesn't happen to me, so I suppose its a computer error. – The Pilot Dude Apr 07 '21 at 15:06
It occurs sometims, but it is working thank youu ;) my other problems the youtube command does not open youtube page but seems to be the llbrary error – Guilherme Candido Apr 07 '21 at 15:17
You could use the `webrowser` built in module. – The Pilot Dude Apr 07 '21 at 15:19

score 0 · Answer 2 · answered Apr 07 '21 at 15:03

0

def takeCommand():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening...")
        audio = r.listen(source)

        try:
        print("Recognizing...")
        command = r.recognize_google(audio, language='en-in')
        print(f"User said: {command}\n")

    except Exception as e:
        print("Say that again please...")
        return "None"

    return command.lower()

answered Apr 07 '21 at 15:03

TANAY T

1
1

Hello, thank you for providing that however there is some errors next to try but if I ident it ikeeps not working – Guilherme Candido Apr 07 '21 at 15:19
Please explain what your code does and how it does it. – M-Chen-3 Apr 07 '21 at 22:47
It takes command, if it is not recognizable then it prints say again :{) – TANAY T Apr 08 '21 at 14:03

Virtual assistant python

2 Answers2