Objects can't have multiple properties with the same key, so
{ "id": 1, "id": 2 }
and { "name": "test", "name": "test2" }
are invalid. I assume that you need an array of ids and an array of names:
[[1, 2, 3], ['test', 'test2', 'test3']]
If all objects are have the same order of keys - ie no { id: 1, name: 'test'}
and { name: 'test2', id: 1 }
, and you need all the values in an object, you can map the objects to their values, and then transpose:
const { pipe, map, values, transpose } = R;
const fn = pipe(
map(values),
transpose,
);
const arr = [{"id":1,"name":"test"},{"id":2,"name":"test2"},{"id":3,"name":"test3"}];
const result = fn(arr);
console.log(result);
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If some objects have a different keys insertion order, you want to change the order of the resulting arrays, or if you need some of the keys, you can get the values with R.props, and then transpose:
const { pipe, map, props, transpose } = R;
const fn = pipe(
map(props(['name', 'id'])), // example - name would be the 1st sub-array
transpose,
);
const arr = [{"id":1,"name":"test"},{"id":2,"name":"test2"},{"id":3,"name":"test3"}];
const result = fn(arr);
console.log(result);
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If you want the structure suggested by Scott Sauyet's:
{
id: [1, 2],
name: ['test1', 'test2']
}
I would map and flatten the objects to an array of pairs with R.chain and R.toPairs, group them by the 1st item in each pair (the original key), and then map each groups item to the last item in each pair (the original value).
const { pipe, chain, toPairs, groupBy, head, map, last } = R
const fn = pipe(
chain(toPairs),
groupBy(head),
map(map(last)), // map(pipe(map(last), uniq)) if you want only unique items
)
const arr = [{"id":1,"name":"test"},{"id":2,"name":"test2"},{"id":3,"name":"test3"}];
console.log(fn(arr))
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