How to create range in swift for 0,5,10 & 1,2,3,4,6,7,8,9:
switch currentIndex {
case 0,5,10:
segment = .fullWidth
case 1,2,3,4,6,7,8,9:// Can't write infinity range here need formula
segment = .fiftyFifty
default:
segment = .fiftyFifty
}
example let underFive:Range = 0.0..<5.0 so I can put underFive in switch case.
If you want a test for multiples of fives
switch currentIndex {
case let x where x.isMultiple(of: 5): // multiples of five here
default: // if you reach here, every value not divisible by five
}
The default case handles your “infinite range” scenario because the values of 5, 10, 15, etc., were handled by the prior case.
In answer to your question, a range is defined by a lower bound, an upper bound, or both. A “partial range” is one that has a lower bound or an upper bound, but not both. E.g. 100... is all integers 100 or larger. Or, combining with the “not multiple of five” logic:
switch currentIndex {
case let x where x.isMultiple(of: 5): // multiples of five here
case 100...: // non multiples of five that are 100 or more
default: // everything else
}
But a range is inherently defined by its upper and lower bounds. If there numbers you wish to exclude, you have to put that logic in an earlier case or add a where clause (or both). Or use Set rather than ranges.
You asked a separate question about constants/variables. You can use that fine:
let underFive = 0..<5
switch currentIndex {
case underFive: // under five
default: // five through 99
}
You only need to make sure that the underlying type of your range matches the type of the currentIndex.
You can use
var currentIndex = 4
enum Segment {
case nothing
case fullWidth
case fiftyFifty
}
var segment: Segment = .nothing
switch currentIndex {
case 0,5,10:
segment = .fullWidth
case 1...4, 6...9 :
segment = .fiftyFifty
default:
segment = .fiftyFifty
}
print(segment)
this code work in playground
