How to extract version number from linux kernel version string or kernel directory listing

Question

For example ls may return string /boot/vmlinuz-5.9.12-100.fc32.x86_64

want a regular expression tool to extract 5.9.12-100

Duplicate of question but additional subject A regex for version number parsing

But because of SO, I can't add my answer...

parsing linux kernel version strings To parse version number from say "/boot/vmlinuz-15.19.12-100.fc32.x86_64" my answer, although b/c of SO i can't do $ echo "/boot/vmlinuz-15.19.12-100.fc32.x86_64" | \ sed -e 's/$^[^0-9]*\-$$[^a-z]*$$.*$/\2/g' -e 's/\.\s*$//g' 15.19.12-100 — user1578821, Mar 27 '21 at 23:54

score 4 · Answer 1 · answered Mar 28 '21 at 00:24

One solution using uname:

$ uname -r
5.4.0-70-generic
$ uname -r | sed -re 's/(^[0-9]*\.[0-9]*\.[0-9]*-[0-9]*)(.*)/\1/'
5.4.0-70

Another one using ls:

$ ls -1 /boot/vmlinuz* | sed -re 's/(^[a-z/]*-)([0-9]*\.[0-9]*\.[0-9]*-[0-9]*)(.*$)/\2/'
5.4.0-67
5.4.0-70

1 Answers1