Taking file input from OpenFileDialog

Question

I looked around for an answer to this and couldn't find anything. All I need to do is take an input from a text file with multiple lines selected from an OpenFileDialog box. Here's a selection from my code:

if (theDialog.ShowDialog() == DialogResult.OK)
        {
            try
            {
                if ((myStream = theDialog.OpenFile()) != null)
                {
                    using (myStream)
                    {
                        //I need this to take input given from OpenFileDialog

                        
                        this.read_display.Text = input;
                    }
                }
            }

I'm probably just overlooking something really obvious, but I'm not sure.

what do you mean by `multiple lines selected from an OpenFileDialog box`?? Multiple files? — Ňɏssa Pøngjǣrdenlarp, Mar 27 '21 at 23:42
Does this answer your question? [Reading a text file using OpenFileDialog in windows forms](https://stackoverflow.com/questions/16136383/reading-a-text-file-using-openfiledialog-in-windows-forms) — Marius, Mar 28 '21 at 00:22

score 0 · Answer 1 · answered Mar 29 '21 at 01:25

0

If you want to get the text from stream, you can create a StreamReader instance and call method ReadToEnd().

string input;
using (StreamReader sr = new StreamReader(myStream))
{
    input = sr.ReadToEnd());
}

answered Mar 29 '21 at 01:25

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Taking file input from OpenFileDialog

1 Answers1