Create File In Directory Error500

Question

I am trying to create a file in a directory using PHP. Both the file and folder have CHMOD: 777. I am trying to make the file to be called image_ (the file count of a directory + 1) My code is

    <button onclick="<?php 
    error_reporting(E_ALL);
    $directory = __DIR__ . "/images/"; $filecount = 0; $files = glob($directory . "*");  if ($files){ 
    $filecount = count($files); }
    $filecount = $filecount + 1;
    $pagename = 'image_'$filecount;

    $newFileName = './images/'.$pagename.;
    $newFileContent = '<?php echo "TEST"; ?>';
    if (file_put_contents($newFileName, $newFileContent) !== false) {
    echo "File created (" . basename($newFileName) . ")";
    } else {
    echo "Cannot create file (" . basename($newFileName) . ")";
    }
    ?> " class="">Upload</button>

I don't really know PHP and this is an amalgamation of code from different places. What do I need to do to stop the ERROR 500

You need to _start_ with checking the error log, to find out what actually went wrong. — CBroe, Mar 25 '21 at 07:44
And also provide us any error you find in logs as mentioned @CBroe. Read following answer to know where to find logs if you are using apache.https://askubuntu.com/a/14767 — Dominik Dosoudil, Mar 25 '21 at 12:53
@Vicky. Thx but im not trying to make a folder, but a file inside a folder — jay_jay0101, Mar 25 '21 at 16:37
@DominikDosoudil the error says ```Parse error: syntax error, unexpected '$filecount' (T_VARIABLE) in /home/vol6_8/epizy.com/epiz_28002566/htdocs/upload.php on line 82 ``` Line 82 is ```$pagename = 'image_'$filecount; ``` — jay_jay0101, Mar 25 '21 at 16:47
I think that the problem is missing `.`. Try `'image_' . $filecount` — Dominik Dosoudil, Mar 25 '21 at 16:51

score 1 · Accepted Answer · answered Mar 25 '21 at 16:52

You are missing one string concatenation at $pagename = 'image_'$filecount; and you are using one more in $newFileName = './images/'.$pagename.;.

Try to edit your PHP code like this

<?php
    error_reporting(E_ALL);
    $directory = __DIR__ . "/images/"; $filecount = 0; $files = glob($directory . "*");  if ($files){ 
    $filecount = count($files); }
    $filecount = $filecount + 1;
    $pagename = 'image_'.$filecount;

    $newFileName = './images/'.$pagename;
    $newFileContent = '<?php echo "TEST"; ?>';
    if (file_put_contents($newFileName, $newFileContent) !== false) {
    echo "File created (" . basename($newFileName) . ")";
    } else {
    echo "Cannot create file (" . basename($newFileName) . ")";
    }
?>

Create File In Directory Error500

1 Answers1