Does Pydroid recognize random.choice?

Question

Here is my code

user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)

and it tells me that it's an invalid variable.

Am I doing something wrong or is it Pydroid's fault?

What do you mean by "it's an invalid variable"? – mkrieger1 Mar 21 '21 at 00:27 — mkrieger1, Mar 21 '21 at 00:27
It says "undefined variable 'random' " E0602 – Frank_Synopsis Mar 21 '21 at 00:31 — Frank_Synopsis, Mar 21 '21 at 00:31

score 1 · Answer 1 · answered Mar 21 '21 at 00:31

1

The only possible issue is that you forgot to

import random

This code is working perfectly fine:

import random
user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)
print(computer_action)

answered Mar 21 '21 at 00:31

AS11

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Are you using Pydroid? – Frank_Synopsis Mar 21 '21 at 00:33
No, I am not using pydroid – AS11 Mar 21 '21 at 00:34
Okay, thanks alot! Importing fixed the issue. I had no idea I had to import – Frank_Synopsis Mar 21 '21 at 00:50

Does Pydroid recognize random.choice?

1 Answers1