PHP: extract name from string

Question

I have a path that looks like:

/home/duke/aa/servers/**servername**/var/...morefiles...

With php, I want to extract the "servername" from the path

Unfortunately I'm not that well versed with php but I came up with something that used strstr() but I am only using PHP version 5.2 where as one of the parameter functions require 5.3

What could be some code that would return "servername"?

What do you mean by "extract" exactly? Do you know the server name? If not, what tells the server name apart from everything else? — Pekka, Jul 12 '11 at 20:09
there are a bunch of folders in /servers/ that represent servername. But my question is I want some function to return **servername** — dukevin, Jul 12 '11 at 20:11
Is the portion of the string before '\*\*servername\*\*' always the same ('/home/duke/aa/servers/'). If not, what variations are possible? — George Cummins, Jul 12 '11 at 20:11
@George the portion of the string before servername is always the same — dukevin, Jul 12 '11 at 21:00

score 8 · Accepted Answer · answered Jul 12 '11 at 20:10

8

you can use explode('/', $path) to break it down into the individual directories. After that, it's up to you to figure out which array element is the server name (with your sample path, it'd be #4):

$parts = explode('/', $path);
echo $parts[4]; // **servername**

answered Jul 12 '11 at 20:10

Marc B

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Darn it, I didn't even think of that. – Phil Jul 12 '11 at 20:12
Wow I over looked explode too! – dukevin Jul 13 '11 at 00:20

powtac · Answer 2 · 2011-07-12T20:15:22.917

6

function getServerName($data) {
    preg_match('#/servers/(.+)/var/#', $data, $result);
    if (isset($result[1]) {
        return $result[1];
    }
}

$data = '/home/duke/aa/servers/**servername**/var/...morefiles...';
echo getServerName($data);

edited Jul 12 '11 at 20:15

answered Jul 12 '11 at 20:10

powtac

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will this working using `+` as the delimiter and having an unescaped `+` in the middle? I would guess you get an unknown modifier ')' error or something about not closing the group. – Jonathan Kuhn Jul 12 '11 at 20:12
thanks this looks promising, I will try this out when I get home! – dukevin Jul 12 '11 at 20:14

score 0 · Answer 3 · answered Jul 12 '11 at 20:16

0

$str = '/home/duke/aa/servers/**servername**/var/...morefiles...';

echo preg_replace('$(.+)/servers/(.+)/var/(.+)$', '\2', $str);

answered Jul 12 '11 at 20:16

Buddy

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PHP: extract name from string

3 Answers3