Consider the following program.
import Control.Monad.State
import Control.Monad.Catch
ex1 :: StateT Int IO ()
ex1 = do
modify (+10)
liftIO . ioError $ userError "something went wrong"
ex2 :: StateT Int IO ()
ex2 = do
x <- get
liftIO $ print x
ex3 :: StateT Int IO ()
ex3 = ex1 `onException` ex2
main :: IO ()
main = evalStateT ex3 0
When we run the program we get the following output.
$ runhaskell Test.hs
0
Test.hs: user error (something went wrong)
However, I expected the output to be as follows.
$ runhaskell Test.hs
10
Test.hs: user error (something went wrong)
How do I preserve the intermediate state in ex1
in the exception handler ex2
?