Numeric validation in Commons Lang

Question

While using the org.apache.commons.lang.math.NumberUtils.isNumber(String str) function, I see that passing a string like "1f" passes validation while passing "1a" fails.

What kind of alphabets are allowed here?

1f(1.0 Float) is regular Java language and 1a not. – fyr Jul 12 '11 at 15:44 — fyr, Jul 12 '11 at 15:44

score 4 · Answer 1 · answered Jul 12 '11 at 15:57

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Jumping on the bandwagon...

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answered Jul 12 '11 at 15:57

mre

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score 2 · Accepted Answer · answered Jul 12 '11 at 15:45

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From the documentation:

Valid numbers include hexadecimal marked with the 0x qualifier, scientific notation and numbers marked with a type qualifier (e.g. 123L).

1f means the float number 1.

answered Jul 12 '11 at 15:45

JB Nizet

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But 1a is a valid hex number. So why it fails? – Victor Jul 12 '11 at 15:51
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0x1a is hex need the 0x (if im not mistaken) – RMT Jul 12 '11 at 15:53

RMT · Answer 3 · 2011-07-12T15:56:32.657

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the 1f is taking the 1 as a float.

"1a" won't be considered as a hexadecimal value because it needs the 0x in front of it,

ex: "0x1a"

edited Jul 12 '11 at 15:56

answered Jul 12 '11 at 15:45

RMT

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Numeric validation in Commons Lang

3 Answers3