How change Switch state only if some condition is true?

Question

I want that my Switch change to checked if some condition is true, else, show a toast informing the user what happen. I'm trying:

switch?.setOnclickListener{
if(condition)   switch!!.isChecked=true
else
//Show toast
}

But i know that condition is false and the switch change to checked. How to do the change of switch only when some condition is true?

This should work. You should check that you are appropriately calculating the condition. — Tenfour04, Mar 07 '21 at 17:25

score 1 · Accepted Answer · answered Mar 07 '21 at 22:02

1

This code should work:

    var condition = true
    if (condition == true) {
        switch.isChecked = true
    } else {
        Toast.makeText(this, "This is a toast", Toast.LENGTH_SHORT).show()
    }

Its also possible that your switch is checked by default, your xml should look something like this:

    <Switch
    android:id="@+id/switch1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:checked="false"
    android:text="Switch" />

If one of the tags is android:checked="true", set it to false.

answered Mar 07 '21 at 22:02

ChocolateChapta

148
2
11

Why does this not work for you? Try to set your condition to `condition = false` directly in front of your `if` clause, if it still gets checked, some other code in your project is the reason, else your condition was just wrong. @mojojojo – ChocolateChapta Mar 08 '21 at 15:15
UPDATE!. Work fine – mojojojo Apr 02 '21 at 04:14

score 0 · Answer 2 · answered Mar 08 '21 at 03:53

Everything seemed to be working for me.

but I found in a different Question that had a similar problem, that they used

checkBox.setChecked(true)
checkbox.jumpDrawablesToCurrentState()

and it worked for them. does any of it help?

here is the original link: Why CheckBox checked not working with Kotlin programmatically?

How change Switch state only if some condition is true?

2 Answers2