program flow when ShowDialogue another window

Question

consider the flowing scenario

chequeInfo = new Check();
                Messenger.Default.Register<Check>(this, (a) => this.doSomething(a));
                AddNewCheck j = new AddNewCheck();
                _dialogService.showDialoge(j);
                Console.WriteLine("this text doesn't show up");
                SpecialCustomerPayments d = new SpecialCustomerPayments();                  
                d.chequeId = chequeInfo.Id;
                d.paymentAmount = chequeInfo.value;
                d.userId = 1;
                ....

as you can observe from code above I'm showDialog() another window in the middle of a method , I expected the flow to continue after I done with the new window , but it is not , I think I'm missing something obvious here, any help will be much appreciated

thanks in advance

score 1 · Accepted Answer · answered Jul 08 '11 at 19:07

1

ShowDialog() is a blocking call.
It will only return when the new window is closed.

If you want it to return immediately and leave the window open, call .Show().

answered Jul 08 '11 at 19:07

SLaks

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thanks for the reply , do u mean after closing the new window , the rest of the method will execute ? that is what I actually expected and that is not happening , I checked using a Console.WriteLine("") – Musaab Jul 08 '11 at 19:16
Then you're probably getting an exception. Click Debug, Exceptions, and check all of the boxes. – SLaks Jul 08 '11 at 19:21

program flow when ShowDialogue another window

1 Answers1