This problem bothered me for an hour when I was programming, but I still didn't know the error of the original method after solving it.
void generate_r_vector(char (*r_vector)[17],char *random_r) {
BIGNUM* vector[127];
char r_v[128][17];
char flag[17];
memset(flag, 0, sizeof(flag));
int bits = 128;
int top = 0;
int bottom = 0;
for (int i = 0; i < 127; i++) {
vector[i] = BN_new();
BN_rand(vector[i], bits, top, bottom);
memset(r_v[i], 0, sizeof(r_v[i]));
BN_bn2bin(vector[i], r_v[i]);
}
memset(r_v[127], 0, sizeof(r_v[127]));
for (int i = 0; i < 127; i++) {
for (int j = 0; j < 16; j++) {
flag[j] = flag[j] ^ r_v[i][j];
}
}
for (int i = 0; i < 16; i++) {
r_v[127][i] = flag[i] ^ random_r[i];
}
for (int i = 0; i < 128; i++) {
memcpy(r_vector[i], r_v[i], 17);
}
}
Using memcpy to copy these arrays, when XOR in the main function, you can get the original string random_r. But using the strcpy function to copy these arrays in the main function XOR, can not get the original random_r.
What I learned about OpenSSL:here, a 128 bit large number is converted into binary, and then every 4 bits are converted into a decimal, which is stored in the char array. Memcpy copies by byte, while strcpy can only copy strings.
I can't understand why the XOR results of the two copy methods are different when they are both stored in char arrays.
My English level is not good, I hope you programmers can understand my expression. I sincerely hope you can answer my question. thank you
=======================2021/2/21 updata===================================== I provide a program that can run directly, hoping to alleviate the problems caused by my unclear expression.
int main() {
char* random_r="1234567891234567";//长度16 算上'\0'17
char r_vector[128][17];
BIGNUM* vector[127];
char r_v[128][17];
char flag[17];//判断是否一致
memset(flag, 0, sizeof(flag));
int bits = 128;
int top = 0;
int bottom = 0;
for (int i = 0; i < 127; i++) {
vector[i] = BN_new();
BN_rand(vector[i], bits, top, bottom);
memset(r_v[i], 0, sizeof(r_v[i]));
BN_bn2bin(vector[i], r_v[i]);
}
memset(r_v[127], 0, sizeof(r_v[127]));
for (int i = 0; i < 127; i++) {
for (int j = 0; j < 16; j++) {
flag[j] = flag[j] ^ r_v[i][j];
}
}
for (int i = 0; i < 16; i++) {
r_v[127][i] = flag[i] ^ random_r[i];
}
//至此生成了128个向量,这些向量的异或之和正好是random_r的值,ans可以验证这个结论
char ans[17];
memset(ans, 0, sizeof(ans));
for (int i = 0; i < 128; i++) {
for (int j = 0; j < 16; j++) {
ans[j] = ans[j] ^ r_v[i][j];
}
}
printf("the target XOR result is:%s\n", ans);//
//下面使用memcpy的形式拷贝并求异或值
for (int i = 0; i < 128; i++) {
memcpy(r_vector[i], r_v[i], 17);//逐字节拷贝解决问题strcpy会出现问题,原因未知
}
memset(ans, 0, sizeof(ans));
for (int i = 0; i < 128; i++) {
for (int j = 0; j < 16; j++) {
ans[j] = ans[j] ^ r_vector[i][j];
}
}
printf("using memcpy copying and the result is:%s\n", ans);//这是正确的结果
memset(r_vector, 0, sizeof(r_vector));
for (int i = 0; i < 128; i++) {
strcpy(r_vector[i], r_v[i]);//strcpy会出现问题,原因未知
}
memset(ans, 0, sizeof(ans));
for (int i = 0; i < 128; i++) {
for (int j = 0; j < 16; j++) {
ans[j] = ans[j] ^ r_vector[i][j];
}
}
printf("using strcpy copying and the result is:%s\n", ans);
int err_count = 0;
for (int i = 0; i < 128; i++) {
if (strcmp(r_vector[i], r_v[i]) != 0) err_count++;
}
printf("after using strcpy() each vector using strcmp() with orignal r_v,the different vector nums:%d\n", err_count);
system("pause");
return 0;
}
Running results in vs2019
the target XOR result is:1234567891234567
using memcpy copying and the result is:1234567891234567
using strcpy copying and the result is:12eH⊙碡?H-c纫
after using strcpy() each vector using strcmp() with orignal r_v,the different vector nums:0