fixed point binary operation with matlab

Question

I have these decimal values:

x1=-43.00488
x4=11.5048
y1=-11.5048
y4=-43.004

I converted them to their equal binary values, in the format Q7.10

So, these are the binary values:

% All of the binary values are signed and in Q7.10 format.

x1=1010100_1111111011   
x4=0001011_1000000101
y1=1110100_0111111011
y4=1010100_1111111011

I want to do this operation with binary values in matlab :

% This line is equal to multiplying "((x1-x4) / (y1-y4))" with 2^10;

 x1x4_div_y1y4 = ((x1-x4) / (y1-y4)) << 10

While trying to do this operation I had some difficulties,

firstly, I couldn't declare the negative binary values in Matlab. secondly, are we allowed to do math operations with binary values or should I do the operations with decimal values then convert them to binary values?

But what I need is to do this operation with binary operations so I can implement it in verilog hdl.

  a= ((-43.00488-11.5048) / (-11.5048+43.00488))*(2^10)

a =

  -1.7720e+03

I am not sure if these statements are given the true answer. Should I multiply it with 2^10 or so...

I want to do the same operation using binary values. Can I do that in Matlab? And how to do that?

Thank you in advance.

Something doesn't look right in the first step. In binary, `x1` is a negative number, but in decimal it is written as positive `43.00488`. — Harry, Feb 18 '21 at 23:06
Also, this part is not valid MATLAB code: `// << 2^10`. Did you mean for this to be a comment? If so, then use `%` to start the comment. Also, if you want to say "shift left by 10 bits", then it should be `<< 10` and not `<< 2^10`. — Harry, Feb 18 '21 at 23:09
@harry yes I mean it as a comment. It should be "%" sorry. How did u make the background of x1 and 43.00488 greys in the comments? May I learn it? — Abdulkadir Arslan, Feb 18 '21 at 23:23
You can use \` like this: \`hello\` will show like this: `hello`. — Harry, Feb 18 '21 at 23:29

Harry · Accepted Answer · 2021-02-19T00:05:07.073

Your question is not very clear. I think you probably need to think about what you want the fixed-point format of x1x4_div_y1y4 to be. I'm not sure if you really want to multiply by 2^10, or you just did that because you thought you needed to.

However, since you stated that's the operation you want to do, I will assume you really wanted to multiply by 2^10.

The code below converts the binary numbers to fixed point, does the calculation you want, then converts the result back to binary.

Your decimal result (-1772) was correct. You just need to convert it back to signed binary. However, be careful because this number cannot be represented in Q7.10 format (because you multiplied by 2^10, so now it's too large).

In the code below, I just assumed you want the result in signed Q16.8 format (which I interpret as 1 sign bit + 16 integer bits + 8 fractional bits). If you want something different, you can just change those numbers.

close all; clear all; clc;

% All of  the binary values are signed and in Q7.10 format.
x1 = '10101001111111011';
x4 = '00010111000000101';
y1 = '11101000111111011';
y4 = '10101001111111011';

% Convert to signed integers
x1 = -bin2dec(x1(1))*2^16 + bin2dec(x1(2:end));
x4 = -bin2dec(x4(1))*2^16 + bin2dec(x4(2:end));
y1 = -bin2dec(y1(1))*2^16 + bin2dec(y1(2:end));
y4 = -bin2dec(y4(1))*2^16 + bin2dec(y4(2:end));

% Convert from integer to fixed point values
x1 = x1 / 2^10;
x4 = x4 / 2^10;
y1 = y1 / 2^10;
y4 = y4 / 2^10;

% The operation I want to do
x1x4_div_y1y4 = ((x1-x4) / (y1-y4)) * 2^10; % << 10

% Convert back to binary...

% Let's assume we want signed Q16.8 output
INTEGER_BITS = 16;
FRACTIONAL_BITS = 8;

% Convert from fixed-point to integer
x1x4_div_y1y4 = round(x1x4_div_y1y4 * 2^FRACTIONAL_BITS);

% Handle the sign bit
if x1x4_div_y1y4 < 0
    x1x4_div_y1y4 = x1x4_div_y1y4 + 2*2^(INTEGER_BITS + FRACTIONAL_BITS);
end

% Convert to binary
x1x4_div_y1y4 = dec2bin(x1x4_div_y1y4, 1+INTEGER_BITS+FRACTIONAL_BITS)

fixed point binary operation with matlab

1 Answers1