Unpacking Tuple in Dictionary Value

Question

i have a tuple of suspects those suspects exist in dictionary and in the dictionary i have a tuple value

i try to unpacking the values to varibles

suspects = (
 {'name': 'Anne', 'evidences': ('derringer', 'Caesarea')},
 {'name': 'Taotao', 'evidences': ('derringer', 'Petersen House')},
 {'name': 'Pilpelet', 'evidences': ('Master Sword', 'Hyrule')},
 )
for t in suspects:
   for name, weapon,location in t.items():

there i got stacked. i try to run python tutor to see a feeback of my faults, but i can't understand how can i extract the specific value with unpacking solution

for examp solution: Name = Anne , Weapon = Derringer , Location = Caesarea

Chance · Answer 1 · 2021-02-17T21:20:25.297

Try this on for size:

suspects = (
 {'name': 'Anne', 'evidences': ('derringer', 'Caesarea')},
 {'name': 'Taotao', 'evidences': ('derringer', 'Petersen House')},
 {'name': 'Pilpelet', 'evidences': ('Master Sword', 'Hyrule')},
 )
for t in suspects:
    name = t['name']
    weapon, location = t['evidences']
    print(name, weapon, location)

Output:

Anne derringer Caesarea
Taotao derringer Petersen House
Pilpelet Master Sword Hyrule

EDIT: If you must unpack twice, here's an uglier way to do it that does unpack twice (key, value) and (weapon, location) :

suspects = (
 {'name': 'Anne', 'evidences': ('derringer', 'Caesarea')},
 {'name': 'Taotao', 'evidences': ('derringer', 'Petersen House')},
 {'name': 'Pilpelet', 'evidences': ('Master Sword', 'Hyrule')},
 )
for t in suspects:
    name = None
    weapon = None
    location = None
    for key, value in t.items():
       if key == "name":
          name = value
       elif key == "evidences":
           weapon, location = value
    print(name, weapon, location)

Or even `name, (weapon, location) = t['name'], t['evidences']` but I think yours is clearer :) — Jon Clements, Feb 17 '21 at 21:10
my mission is to use at least twice in unpacking method to solve this — Johny8462, Feb 17 '21 at 21:13

score 0 · Answer 2 · answered Feb 17 '21 at 21:10

0

This would be the way to do it:

for t in suspects:
    weapon, location = t["evidences"]
    print(f"Name: {t['name']} Weapon: {weapon} Location: {location}")

answered Feb 17 '21 at 21:10

carloslockward

335
3
8

ddejohn · Answer 3 · 2021-02-17T21:21:11.443

0

Your data structure isn't conducive to what you're trying to do exactly. If there's a specific reason why you want to keep this particular structure, then use the answers provided. If, however, you're open to using a different data structure:

suspects = {"Anne": ("derringer", "Caesarea"),
            "Taotao": ("derringer", "Petersen House"),
            "Pilpelet": ("Master Sword", "Hyrule")}

for name, (weapon, location) in suspects.items():
    print(name, weapon, location)

Output:

Anne derringer Caesarea
Taotao derringer Petersen House
Pilpelet Master Sword Hyrule

edited Feb 17 '21 at 21:21

answered Feb 17 '21 at 21:16

ddejohn

8,775
3
17
30

its a part from mission that i have to solve this with unpcaking method in this data structure i know that if i change the data structure its woukd be very comfort to solve ... thank for your answer – Johny8462 Feb 17 '21 at 21:20

Unpacking Tuple in Dictionary Value

3 Answers3