In the book C Programming by K.N.King,
...
case 3: printf("Current balance: $%.2f\n", balance); break; case 4: return 0; default: printf("Commands: ..."); break;
...
Note that the return statement is not followed by a break statement. A break immediately following a return can never be executed, and many compilers will issue a warning message.
I expected my compiler (usually GCC) would issue a warning message, so I deliberately use break statement in my program right after the return statement to 0 as below.
case 4: printf("Exit the program\n");
return 0;
break; /*** My gcc compiler doesn't issue any error ***/
But my compiler didn't make any error message like below.
C:\Users\user>gcc -Wall -w -o balance balance.c
/* Normally compiled */
Does my GCC compiler have problem? If not, Did the book by K.N.K not reflect recent compiler version?