I am trying to run this code but it's not working. I don't know how to return the input j as a string. This is the error /tmp/D2FFE31F-B533-48DF-AC15-F1EA8A029FCF.q0h9za/main.swift:15:1: error: missing return in a function expected to return 'String'
func FizzBuzz(j:Int) -> String {
if j % 5 == 0 && j % 3 == 0 {
return "FizzBuzz"
}
else if j % 3 == 0 {
return "Buzz"
}
else if j % 5 == 0 {
return "Fizz"
}
}
for i in 0...100 {
print(FizzBuzz(j:i))
}
Adding on to @rob mayoff's answer, the problem is also that you must return a string in that function, because you said so:
// must return a String
func FizzBuzz(j:Int) -> String {
So look in your function. What if j is not divisible by 5, or 3? Your code will just fall through the if else, and none of the returns will be called.
To fix this, just do a return at the end of your function.
func FizzBuzz(j:Int) -> String {
if j % 5 == 0 && j % 3 == 0 {
return "FizzBuzz"
} else if j % 3 == 0 {
return "Buzz"
} else if j % 5 == 0 {
return "Fizz"
}
return "\(j)" /// return the number
}
Swift strings have a feature called “string interpolation”. When a string contains the characters \( followed by some expression followed by ), Swift evaluates (runs) the expression and converts the result to a string, and substitutes that result string into the enclosing string. For example:
"two plus three is \(2 + 3)"
Above, Swift computes 2 + 3, getting the Int 5, then converts the Int 5 into the string "5", then substitutes that into the enclosing string, getting "two plus three is 5".
So one way to return j as a string is to use string interpolation like this:
return "\(j)"
Short answer: “if” statements always need an “else” to return a result.
You have 3 if/else if statements, but no final “else” if those fail.
You need to add either
else {
return “”
}
Or just a final
return “”
