How to fixed an error message : "trying to access array offset on value of type null." at a $record syntax?

Question

I need to display an id number from "kategori_barang" table. When I submitted the code, I get an error message which says "trying to access array offset on the value of type null". Somebody can figure this out? Thanks for the help.

//the title
<h3>Form Edit Kategori</h3>

//syntax for open a controller 
<?php echo form_open('kategori/edit'); ?>
 
//list for display an id number
<input type="text" value="<?php echo $record['kategori_id'];?>" name="id">
<table border="1">
    <tr>
        <td>Nama Kategori</td>
        <td><input type="text" name="kategori" placeholder="kategori" 
                   value="<?php echo $record['nama_kategori'];?>"></td>
    </tr>
    <tr>
        <td colspan="2"><button type="submit" name="submit">Submit</button></td>
    </tr>
</table>
</html>

function edit() { if(isset($_POST['submit'])){ //proses kategori $this->model_kategori->post(); redirect('kategori'); } else{ $id = $this->uri->segment(3); echo $id; $data['record'] = $this->model_kategori->get_one($id)->row_array(); $this->load->view('kategori/form_edit', $data); } } — ry_eryhaqeem, Jan 29 '21 at 11:38
function edit() { $data = array( 'nama_kategori'=> $this->input->update('kategori') ); $this->db->where('kategori_id', $this->input->post(id)); $this->db->update('kategori_id', $data); } — ry_eryhaqeem, Jan 29 '21 at 11:40

score 0 · Answer 1 · answered Jan 29 '21 at 11:14

the error means that your $record array has no such key. either use

isset($record['kategori_id']) ? $record['kategori_id'] : 0;

or dump the $record to logs to see what is inside like this

error_log( print_r($record, TRUE) );

and take it from there....it looks like your $record has nothing in it

How to fixed an error message : "trying to access array offset on value of type null." at a $record syntax?

1 Answers1