access to this array data

Question

i have this array result with print_r:

Array
(
    [0] => stdClass Object
        (
            [id] => 
            [place_id] => ChIJ7w0gwihoXz4R4F5KVQWLoH0
            [label] => Address Downtown - Sheikh Mohammed bin Rashid Boulevard - Dubai - United Arab Emirates
            [value] => Address Downtown - Sheikh Mohammed bin Rashid Boulevard - Dubai - United Arab Emirates
            [details] => stdClass Object
                (

but i need to get place_id property, how i can get this?

i´m trying with data[0]->place_id data["place_id"] but always returned me local.ERROR: Illegal string offset 'place_id'

update

if($select == "address"){
                    $aux = $google->getGoogleAddress($select);

                    print_r(json_decode($aux[0]->place_id));
                    /*$this->newData["place_id"] = $aux["place_id"];
                    $google->generateURL($this->newData);*/

SOLUTION

json_decode($aux)[0]->place_id

thanks for help

Can you share the actual code? It seems like you might be operating on something different than you think. — El_Vanja, Jan 18 '21 at 11:22
@lagbox this is error with your code: local.ERROR: Trying to get property 'place_id' of non-object — daviserraalonso, Jan 18 '21 at 11:32
@El_Vanja i have one return json_encode and i need to access this. i´m doin json_decode and print_r for this, i have result that i have in my question, but i need to acces to place_id, property — daviserraalonso, Jan 18 '21 at 11:33
Please *show the code*. Don't describe what you're working with, because that's where the error is - you don't seem to be working with what you think it should be. — El_Vanja, Jan 18 '21 at 11:35
@lagbox i´m doing print_r for return print_r(json_decode($aux[0]->place_id)); and i can see in console, Array of my question — daviserraalonso, Jan 18 '21 at 11:35
Well there it is - you can't just decode "in advance". `json_decode($aux[0]->place_id)` should be `json_decode($aux)[0]->place_id`. — El_Vanja, Jan 18 '21 at 11:37

score 1 · Accepted Answer · answered Jan 18 '21 at 11:43

The error is in the misunderstanding how decoding works. What you're doing:

json_decode($aux[0]->place_id)

fails because $aux is a string. Which means you're trying to do both array and object property access on it while it's still a string.

In order to receive an array, the JSON string needs to be fully decoded first:

$decoded = json_decode($aux);

After that, $decoded is an array of stdClass objects and $decoded[0]->place_id should contain what you need. You can, however, do it in one step (in case you don't have to use any other portions of the data):

json_decode($aux)[0]->place_id

score 0 · Answer 2 · edited Jan 18 '21 at 11:43

There is a possible issue with place_id key - it is treated as an array of chars(which causes an error of key accessing).

In order to fix this case - you need to convert result to an array trying one of these workarounds:

If this stdClass was retrieved via PDO from database - fetch results as an array instead of an object:

$result = $sth->fetchAll(\PDO::FETCH_ASSOC);

If it was retrieved from other place like file - force casting results to array:

$result = (array) $results;

access to this array data

2 Answers2