I checked This stackoverflow post, but I still cannot understand.
I have this code (yes I know <functional>
achieves the same thing) which worked (if memory serves me right, it was gcc6) and now fails with gcc9.3.0
Given these class definitions
template <typename D>
class Callback{
public:
virtual void operator()(D d)=0;
virtual ~Callback(){}
};
template <>
class Callback <void>{
public:
virtual void operator()()=0;
virtual ~Callback(){}
};
and these definitions
template <typename D,typename P>
struct ParamFunctionType{
typedef void (*value)(D,P);
};
template <typename P>
struct ParamFunctionType<void,P>{
typedef void (*value)(P);
};
I have these subclasses
template <typename D, typename P, typename ParamFunctionType<D,P>::value f>
class FunctionParamCallback:public Callback<D>
{
P p;
FunctionParamCallback(const P& pp) : p(pp) {}
void operator()(D d) { (*f)(d,p); }
};
template <typename P, void (*f)(P)>
class FunctionParamCallback<void, P, f> : public Callback<void>
{
P p;
FunctionParamCallback(const P& pp) : p(pp) {}
void operator()() { (*f)(p); }
};
Now the second definition seems a specialization to me (for D set to void), but I get the following error
error: partial specialization ‘class helium::scb::FunctionParamCallback<void, P, f>’ is not more specialized than [-fpermissive]
297 | template <typename P,void (*f)(P)> class FunctionParamCallback<void,P,f>:public Callback<void>{
| ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
../../helium/signal/callback.h:284:85: note: primary template ‘template<class D, class P, typename helium::scb::ParamFunctionType<D, P>::value f> class helium::scb::FunctionParamCallback’
284 | template <typename D,typename P,typename ParamFunctionType<D,P>::value f> class FunctionParamCallback:public Callback<D>{
|
What am I mistaking?
(a MVCE is provided by Jarod42 here).