Filter xml element removing duplicated child node with groovy xml slurper

Question

I need to filter an xml list so to get all the "element" with no duplicates. Input:

<List>
<element>
    <field1>A</field1>
    <field2>1</field2>
</element>
<element>
    <field1>B</field1>
    <field2>2</field2>
</element>
<element>
    <field1>B</field1>
    <field2>2</field2>
</element>

output

<List>
<element>
    <field1>A</field1>
    <field2>1</field2>
</element>
<element>
    <field1>B</field1>
    <field2>2</field2>
</element>

How is it possibile to achieve this with XmlSlurper or XmlParser in groovy? Thank you.

Please add the code you have tried and how it failed (e.g. errors, stacktraces, logs, ...) so we can improve on it. — cfrick, Jan 16 '21 at 08:44
Is it possible to use findAll and to remove dplicates with that? — James Taylor, Jan 17 '21 at 20:26

score 1 · Accepted Answer · answered Jan 18 '21 at 14:54

Something like this is an option:

import groovy.xml.* 

def data = '''
<List>
<element>
    <field1>A</field1>
    <field2>1</field2>
</element>
<element>
    <field1>B</field1>
    <field2>2</field2>
</element>
<element>
    <field1>B</field1>
    <field2>2</field2>
</element>
</List>'''

def xml = new XmlParser().parseText(data)

def writer = new StringWriter() 
def result = new MarkupBuilder(writer).List { 
  xml.element.unique { 
    it.field1.text()
  }.each { n ->
    element { 
      field1(n.field1.text())
      field2(n.field2.text())
    }
  }
}

println writer

which when run prints:

─➤ groovy solution.groovy
<List>
  <element>
    <field1>A</field1>
    <field2>1</field2>
  </element>
  <element>
    <field1>B</field1>
    <field2>2</field2>
  </element>
</List>

Filter xml element removing duplicated child node with groovy xml slurper

1 Answers1