Function to find area of a rectangle with given cartesian coordinates

Question

Have the function RectangleArea(strArr) take the array of strings stored in strArr, which will only contain 4 elements and be in the form (x y) where x and y are both integers, and return the area of the rectangle formed by the 4 points on a Cartesian grid. The 4 elements will be in arbitrary order. For example: if strArr is ["(0 0)", "(3 0)", "(0 2)", "(3 2)"] then your program should return 6 because the width of the rectangle is 3 and the height is 2 and the area of a rectangle is equal to the width * height.

For example -

Input: ["(1 1)","(1 3)","(3 1)","(3 3)"]
Output: 4

Input: ["(0 0)","(1 0)","(1 1)","(0 1)"]
Output: 1

In your 2 examples, the sequence of coordinates is different. — Nikhil Patil, Jan 07 '21 at 06:18
@NikhilPatil it should actually return the answer based on that input sequence — Sam, Jan 07 '21 at 06:57

score 1 · Accepted Answer · answered Jan 07 '21 at 06:31

1

Below function will work provided you input the correct set of coordinates of rectangle

function distance(coord1, coord2) {
  console.log(coord1, coord2);
  return Math.sqrt(Math.pow(coord1[0] - coord2[0], 2) + Math.pow(coord1[1] - coord2[1], 2));
}

function RectangleArea (strArr) {
  if (strArr.length < 4) {
    throw new Error("invalid array passed");
  }
  const numArr = strArr.map(coord => coord.match(/\d/g));

  const width = distance(numArr[0], numArr[1]);
  const height = distance(numArr[1], numArr[2]);
  console.log(width, height);

  return width * height;
}

answered Jan 07 '21 at 06:31

Tulsi Ram

304
2
7

Well for the example test cases, it gave me the wrong answer – Sam Jan 07 '21 at 06:56
1

5.656 for the first – Sam Jan 07 '21 at 06:58
Got it after some changes. Thanks for the help. – Sam Jan 07 '21 at 07:00

score 0 · Answer 2 · answered May 28 '21 at 16:15

Java Solution:

 public int product(String[] strArr){ 
    int firstValue = Integer.parseInt(String.valueOf(strArr[0].charAt(1)));
    int secondValue = Integer.parseInt(String.valueOf(strArr[0].charAt(3)));
    int height = 0;
    int width= 0;

    for(int i=1; i<strArr.length;i++){
        if(Integer.parseInt(String.valueOf(strArr[i].charAt(1)))==firstValue){
            height = secondValue - Integer.parseInt(String.valueOf(strArr[i].charAt(3)));
        }
        if(Integer.parseInt(String.valueOf(strArr[i].charAt(3)))==secondValue){
            width = firstValue - Integer.parseInt(String.valueOf(strArr[i].charAt(1)));
        }
    }

    return Math.abs(height*width);
}

score 0 · Answer 3 · answered Dec 14 '21 at 14:47

0

//c++ code
#include <bits/stdc++.h>
using namespace std;
int product(vector<string>arr){
int fistvalue= arr[0][1]-'0';
int secondvalue=arr[0][3]-'0';
int height=0;
int width=0;
for(int i=1;i<arr.size();i++){
    if(arr[i][1]-'0'==fistvalue){
        height=secondvalue-(arr[i][3]-'0');
    }
    if(arr[i][3]-'0'==secondvalue){
        width=fistvalue-(arr[i][1]-'0');
    }
}
return abs((height*width));
}
int main(){
cout<<product({"(0 0)", "(3 0)", "(0 2)", "(3 2)"});
return 0;}

answered Dec 14 '21 at 14:47

Kuldeep yadav

1

Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Dec 14 '21 at 15:11

Function to find area of a rectangle with given cartesian coordinates

3 Answers3