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I have a Ruby code as shown below, Try it online!

loop{p$.+=1r}

and another one, in which I just divide the 1r by 2 as shown below, Try it online!

loop{p$.+=1r/2}

As far as I can guess, the type-casting isn't working properly with $.. In the first case, it works correctly, but in the second one, it doesn't. strange!

So, why it works that way? Or, maybe my guess is wrong, then what is the actual issue, and how to resolve it?

Usually, Integer are up-casted to more complex data types, like in this code, it seems to work.

vrintle
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  • `x=0r; loop{p x+=1/2r}` works, trying to change the class of the $. variable wont. – Jad Jan 03 '21 at 16:46

1 Answers1

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it works correctly, type of the $. variable is Integer

puts $..class. # => Integer

So right side of the addition will be casted to the Integer.
In first case 1r is casted to the Integer of value 1, so you can see value is changing.

In second case 1r/2 is casted to the Integer of value 0, so you don't see changes because adding zero will not change original value.

You can not change type of pre-defined global variable, just try $. = "text"

Fabio
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