How to evaluate without unnecessary parentheses in Julia?

Question

I have a case struct which holds an expression with the type of SymbolicUtils.Term{Bool}. Also I have defined rules from SymbolicUtils library which takes these cases as input and simplifies them. In order to simplify these cases the form should be like: (i == j) & (i == 3) & (j == 3) & (i == 3) & (j == 3) without unnecessary parentheses. For example it's not good to have this one: ((i == j) & ((i == 3) & (j == 3))) & ((i == 3) & (j == 3))

In order to solve this, I thought I can convert the expression with extra parentheses to string then I can process this string to get the desired form. I did this actually:

function reduce_parentheses(case::Case)
   main_exp_string = ""
   exp_to_str = repr(case.condition) #Convert case's condition into a string.
   condition_list = split(exp_to_str, "&") #Split cases to subcases into a list.
   for i in 1:length(condition_list) # Iterate cases list one by one.
      stripped = lstrip(condition_list[i], [' ']) #Remove the whitespace at the beginning of the expression.
      stripped = rstrip(stripped, [' ']) #Remove the whitespace at the end of the expression.

      stripped = lstrip(stripped, ['(']) #Add opening parentheses at the beginning of the expression.
      stripped = rstrip(stripped, [')']) #Add closing parentheses at the end of the expression.

      #Get the desired form.
      if i != 1
         main_exp_string = main_exp_string * ' ' * '(' *stripped * ')'
      elseif i == 1
         main_exp_string = main_exp_string * '(' *stripped * ')'
      end
      if i != length(condition_list)
         main_exp_string = main_exp_string * ' ' * '&'
      end

    end
    println(main_exp_string)
    exp = (Meta.parse(main_exp_string)) #Convert string back to an expression.
    println(typeof(eval(exp))) #Convert expression back to SymbolicUtils.Term{Bool} type.
end

I can get the string in the desired form but when I try to turn it back into an expression I'm getting unnecessary parentheses with the different form because it's evaluating left to right I think.

Example:

The case with unnecessary parentheses: ((i == j) & ((i == 3) & (j == 3))) & ((i == 3) & (j == 3))

The processed string(desired form): (i == j) & (i == 3) & (j == 3) & (i == 3) & (j == 3)

Evaluated case: ((((i == j) & (i == 3)) & (j == 3)) & (i == 3)) & (j == 3)

How can I solve this? Maybe instead of converting it into a string can I do it in a smarter way?