I have some particular dimensionless numbers commonly used in fluid mechanics. I want to express a certain expression in terms of these variables.
If I define my dimensionless numbers and then do
simplify(*expression*)
where the expression is a function of variables that have all been used at least once in the definition of the dimensionless numbers, is it able to give this expression in terms of these dimensionless numbers? Can it be used to save time with this sort of algebra?
Many thanks !
E.g dimensionless numbers :
Re = (\rho U_0 H_0) / \mu
Ca =( \mu U_0 )/ (\sigma)
St = (T_0 U_0)/H_0
Fr = U_0 /(\sqrt(G_0 H_0))
Oh = (\mu}/\sqrt( \rho \sigma H_0)
Bo =(\rho G_0 H_0^2) /\sigma
If I do :
simplify(G_0 H_0 / U_0 ^2)
Will it give the answer as 1/Fr^2
Or would I instead need to type something like :
simplify(( G_0/H_0 U_0), )Fr=...)
So e.g will it tell me what combination of dimensionless numbers I can write \mu/(U_0^2 H_0) as, if I write :
Simplify ( mu/U_0^2 H_0 )
Or :
Simplify (( \mu/(T_0 H_0) ) , Re=...,Fr=...,Ca=...St=..., Bo=..., Oh=...)