0

I know how to solve in Mathematica with EllipticF:

EllipticF[ζI[P], k2[P]] - EllipticF[ζr[P, r], k2[P]]

That's basically what i want to do in Python. I've tried many thing to use such as the function scipy.special.ellipj, but it returns a list and i want a number. Please, does anyone know how to solve this problem?

nicoguaro
  • 3,629
  • 1
  • 32
  • 57
Isabella Nunes
  • 59
  • 1
  • 6
  • 2
    Please provide a [mcve], as well as the current and expected output. – AMC Dec 24 '20 at 01:46
  • Maybe [this blogpost of John Cook](https://www.johndcook.com/blog/2018/10/12/jacobi-function-nomenclature/) is useful here? – JohanC Dec 24 '20 at 12:10

1 Answers1

1

The equivalent to Mathematica's EllipticF in SciPy is scipy.special.ellipkinc.

For example, in Wolfram Alpha, EllipticF(3/4, 1/10) gives the numerical value 0.7564213553633020688976920....

With SciPy,

In [49]: from scipy.special import ellipkinc                                                                                               

In [50]: ellipkinc(0.75, 0.1)                                                                                                              
Out[50]: 0.7564213553633021

(I don't know what the arguments are that you are passing to EllipticF, so I can't help you with those.)

Warren Weckesser
  • 110,654
  • 19
  • 194
  • 214