How to find all the data of object by given id in javascript

Question

How to find all the data of object by given id. For example this is my array of obbject:

const array = [{
    "name": "max",
    "id": 10
  },

  {
    "name": "ram",
    "id": 20
  },

  {
    "name": "sita",
    "id": 30
  },

  {
    "name": "bill",
    "id": 10
  },
]

Now i wanna create function that returns all data that has id of 10. The function should return, {"name": "max", "id": 10} and {"name": "bill", "id": 10}.

I tried doing this:

const array = [{
    "name": "max",
    "id": 10
  },

  {
    "name": "ram",
    "id": 20
  },

  {
    "name": "sita",
    "id": 30
  },

  {
    "name": "bill",
    "id": 10
  },
]

function findData(data, id) {
  const found = data.find(element => element.id === id)
  return found
}

console.log(findData(array, 10))

but the problem is, it just returns one object instead of returning all the data

use `filter`. `find` return first matching condition... `filter` returns all matching condition — Nilesh Patel, Dec 23 '20 at 13:50
The whole point of IDs is that they're unique. Maybe start there. — Jonathan, Dec 23 '20 at 13:50

score 1 · Answer 1 · edited Dec 23 '20 at 13:53

1

Use Array.filter()

const array = [
  { name: 'max', id: 10 },

  { name: 'ram', id: 20 },

  { name: 'sita', id: 30 },

  { name: 'bill', id: 10 }
];

function findData(data, id) {
  return data.filter(element => element.id === id);
}

console.log(findData(array, 10));

edited Dec 23 '20 at 13:53

michael

4,053
2
12
31

answered Dec 23 '20 at 13:50

wangdev87

8,611
3
8
31

score 0 · Answer 2 · answered Dec 23 '20 at 13:50

you could use Array#filter instead of Array#find

const array = [ {"name": "max", "id": 10 }, {"name": "ram", "id": 20 }, {"name": "sita", "id": 30 }, {"name": "bill", "id": 10 }, ]

function findData(data, id){
    const found = data.filter(element => element.id === id)
    return found
}

console.log(findData(array, 10))

How to find all the data of object by given id in javascript

2 Answers2