Python FFmpeg not accepting Path

Question

I made this script

import os
import sys
import subprocess
from tkinter import *
from tkinter import filedialog
print("Compressing......")
file_path = filedialog.askopenfilename(title = "Select Video", filetypes = (("Mp4", "*.mp4"), 
            ("AVI", "*.avi"), ("MOV", "*.mov"), ("3gp", "*.3gp")))
print (file_path)
result = subprocess.run("TOOLS\\ffmpeg.exe -i "+ (str(file_path))+"-b 800k output.mp4")
print("Process Succesfull")

But When I run it and selects a file this error is comming-

Traceback (most recent call last):
  File "D:\Compressor.py", line 10, in <module>
    result = subprocess.run("TOOLS\\ffmpeg.exe -i "+ (str(file_path))+"-b 800k output.mp4")
  File "C:\Program Files\Python37\lib\subprocess.py", line 488, in run
    with Popen(*popenargs, **kwargs) as process:
  File "C:\Program Files\Python37\lib\subprocess.py", line 800, in __init__
    restore_signals, start_new_session)
  File "C:\Program Files\Python37\lib\subprocess.py", line 1207, in _execute_child
    startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified

Can Anybody help me Can Anybody help me Can Anybody help me

You're probably going to need at least one space between the filename and "-b 800k output.mp4". My recommendation is to build the string you're passing to `subprocess.run` as a variable so that you can examine it before trying to run it. — Bryan Oakley, Dec 22 '20 at 19:30

Python FFmpeg not accepting Path

0 Answers0