Passing the Values of an array to a function (not the array itself)

Asked Dec 11 '20 at 18:05

Active Dec 11 '20 at 18:16

Viewed 18 times

I have a function that has 5 requqired parameters and 2 optional ones. So a user can input 5-7 parameters and they are stored inside of an array. How can I pass those values to the function, is there something similar like extract() that returns the values and not the numbers?

E.g.:

$arr = ['one', 'two', 'three', 'four', 'five', 'six'];
functionname($arr[0], $arr[1], $arr[2],$arr[3],$arr[4],$arr[5])

doesn't work, because I never know for sure if the sixth parameter really exists. Thanks for any help.

edited Dec 11 '20 at 18:16

asked Dec 11 '20 at 18:05

kledo-34

Does [call_user_func_array](https://www.php.net/manual/en/function.call-user-func-array.php) fit the bill? – Greg Schmidt Dec 11 '20 at 18:09
Check out the [spread operator](https://www.php.net/manual/en/functions.arguments.php#example-163) – Chris Haas Dec 11 '20 at 18:09
Have a look at argument unpacking http://docs.php.net/manual/en/migration56.new-features.php#migration56.new-features.splat – Sindhara Dec 11 '20 at 18:10
Sure it does, thanks a lot for your help, I really appreciate that :) – kledo-34 Dec 11 '20 at 18:10
Thanks for all your comments problem is solved ;) – kledo-34 Dec 11 '20 at 18:11
@ChrisHaas in PHP it's **splat** operator. – AbraCadaver Dec 11 '20 at 18:25
1

Thanks @AbraCadaver, I stand corrected and I can guarantee that by tomorrow I'll forget it once again! – Chris Haas Dec 11 '20 at 19:01

Passing the Values of an array to a function (not the array itself)

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