"test".partition("s") calls partition from Enumerable module instead of String module

Question

I have tried to partition a string using the partition method from the String module. However, when doing so:

puts "test".partition("s")

I get the following error message:

Line 1:in `partition': wrong number of arguments (1 for 0) (ArgumentError) from t.rb:1

I believe that Ruby calls the partition method from the Enumerable module, instead of the one from the String module as I wanted.

How can I get Ruby to call the desired method?

Can you put the output of the following in irb: >> RUBY_VERSION >> "test".partition("s") If you're using Ruby 1.8.6, String#partition doesn't do what you think — Lee Jarvis, Jun 29 '11 at 09:40
@Jan that's why it's not working, you're viewing documentation for 1.8.7 or 1.9.2. You're using an ancient version of Ruby. I recommend upgrading to either 1.8.7 or 1.9.2 — Lee Jarvis, Jun 29 '11 at 09:43
irb(main):001:0> RUBY_VERSION => "1.8.4" irb(main):002:0> "test".partition("s") ArgumentError: wrong number of arguments (1 for 0) from (irb):2:in `partition' from (irb):2 — Jan-Willem, Jun 29 '11 at 09:46
I once came across a similar issue in Rubinius: https://github.com/rubinius/rubinius/issues/1005 — Andrew Grimm, Jun 29 '11 at 11:52
I tripped over this problem (reading the wrong docs) recently in Regex#match and String#match, which take an optional second parameter (offset) in 1.9.3. The search was compounded by my text editor starting rspec with ruby 1.8.7, while my tests in irb were using 1.9.3. :-) — sheldonh, Nov 07 '11 at 20:35

score 2 · Accepted Answer · edited May 23 '17 at 11:50

2

As injekt has pointed out, 1.8.4 is too old. APIdock shows that String#partition only appears in 1.8.7. Upgrade.

edited May 23 '17 at 11:50

Community

answered Dec 16 '11 at 00:41

Martin Vidner

1 Answers1