Finding first multiple of 5 for a value in my program

Question

I can't figure out how to do something very simple in my program.

Given a float value f (it could be 0, or it could be 5 million, etc), I need to find the first value x such x >= f (x is greater than f) and x is a multiple of 5.

Related: http://stackoverflow.com/questions/5976832/what-does-the-double-do-in-ceildouble — Sven Marnach, Jun 28 '11 at 13:37

score 1 · Accepted Answer · answered Jun 28 '11 at 13:33

1

Divide by 5, round up to the next integer (using ceil() or similar), multiply by 5 again.

answered Jun 28 '11 at 13:33

Sven Marnach

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can you show me how to use ceil? This is an Objective-C program. – CodeGuy Jun 28 '11 at 13:34
Objective C is still C, you have access to ``. – Blindy Jun 28 '11 at 13:36
@reising: `ceil(3.5)` yields 4. – Sven Marnach Jun 28 '11 at 13:36

score 0 · Answer 2 · answered Jun 28 '11 at 13:39

0

You can use modulo operator and do something like:

x = f - f % 5 + 5

answered Jun 28 '11 at 13:39

Daniel Hernik

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f is float, and even truncated to int then it will break for multiples of 5. – taskinoor Jun 28 '11 at 13:50

Finding first multiple of 5 for a value in my program

2 Answers2