The perfect number after 28

Question

I've written a simple program to find the perfect number that is immediately after 28 (which is 496), however it is not working. Not sure what I'm doing wrong.

#include <stdio.h>

int main(){

    int num=29, sum=0, aux=1;

    while(aux!=0){
        for(int i=1; i<num; i++){
            if(!(num%i)){
                sum+=i;
            }
        }

        if(sum == num){
            printf("%d", sum);
            aux=0;
        }else{
            num++;
        }
    }

    return 0;
}

Not using a debugger was your first mistake. – Martin James Nov 28 '20 at 01:52 — Martin James, Nov 28 '20 at 01:52
Rather than `for(int i=1; i – chux - Reinstate Monica Nov 28 '20 at 04:44 — chux - Reinstate Monica, Nov 28 '20 at 04:44

score 1 · Accepted Answer · answered Nov 28 '20 at 01:45

1

You must initialize sum before each check.

    while(aux!=0){
        sum = 0; /* add this */
        for(int i=1; i<num; i++){

answered Nov 28 '20 at 01:45

MikeCAT

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11
45
70

score 0 · Answer 2 · answered Nov 28 '20 at 03:38

0

You should have initialized the value of sum inside the while loop because it's value is not getting reset to 0 after a number check and it keeps on increasing the later value , so finally it would be resulting in a error .

answered Nov 28 '20 at 03:38

yugsharma1711

71
1
9

The perfect number after 28

2 Answers2