How to fix the appearance of unexpected characters in string counts

Question

This code prints a table of the letters of the alphabet in alphabetical order which occur in the string together with the number of times each letter occurs. There are two unwanted numbers in this code which are 8 and .1 but I do not know how to remove them from the output.

 s = 'ThiS is String with Upper and lower case Letters.'

 # Or see Python's Counter class: counts = Counter(s.lower())
counts = {}
for c in s.lower():
    counts[c] = counts.get(c, 0) + 1

for c, n in sorted(counts.items()):
    print(c, n)

I do not want that in the output lol. How can I change that so that those two numbers do not show? — Johhhbb, Nov 27 '20 at 21:43
See https://stackoverflow.com/questions/15558392/how-can-i-check-if-character-in-a-string-is-a-letter-python — PM 77-1, Nov 27 '20 at 21:46

score 2 · Answer 1 · answered Nov 27 '20 at 22:03

Purely for fun ... you could do it all in two lines if you really wanted. :-)

String:

 s = 'ThiS is String with Upper and lower case Letters.'

Ridiculousness:

chars = [i for i in s.lower() if i.isalpha()]
print(*sorted({c: chars.count(c) for c in chars}.items(), key=lambda x: x[1], reverse=True), sep='\n')

Output:

('t', 5)
('s', 5)
('e', 5)
('i', 4)
('r', 4)
('h', 2)
('n', 2)
('w', 2)
('p', 2)
('a', 2)
('l', 2)
('g', 1)
('u', 1)
('d', 1)
('o', 1)
('c', 1)

score 1 · Answer 2 · answered Nov 27 '20 at 21:46

1

So,You can remove spaces and dots from the input string.

s = 'ThiS is String with Upper and lower case Letters.'

s=s.replace(" ","").replace(".","")# remove spaces and dots from the input string

counts = {}
for c in s.lower():
    counts[c] = counts.get(c, 0) + 1

for c, n in sorted(counts.items()):
    print(c, n)

[Output]:

a 2
c 1
d 1
e 5
g 1
h 2
i 4
l 2
n 2
o 1
p 2
r 4
s 5
t 5
u 1
w 2

answered Nov 27 '20 at 21:46

AziMez

2,014
1
6
16

2

Instead of chaining `replace`s, you can do this in a more pythonic way: `s = "".join(c for c in s if c.isalpha())` – kn0wmad1c Nov 27 '20 at 21:51

score 1 · Answer 3 · answered Nov 27 '20 at 21:56

1

It looks like it's counting spaces and periods in the string as well. Replacing them with "" is an easy way to fix this.

answered Nov 27 '20 at 21:56

AureliusAtillius

43
3

score 1 · Answer 4 · answered Nov 27 '20 at 23:33

1

import string
from collections import Counter
s = "".join(filter(lambda c: c in string.ascii_letters, s))
for c, count in Counter(s).items():
    print(c, count)

answered Nov 27 '20 at 23:33

Daniel Meltzer

349
1
3
10

score 0 · Answer 5 · answered Nov 28 '20 at 00:21

You can simply count them using str.count() with a simple check of isalpha():

s = 'ThiS is String with Upper and lower case Letters. 81'
{char: s.count(char) for char in s.lower() if char.isalpha()}

results in:

{'t': 4,
 'h': 2,
 'i': 4,
 's': 3,
 'r': 4,
 'n': 2,
 'g': 1,
 'w': 2,
 'u': 0,
 'p': 2,
 'e': 5,
 'a': 2,
 'd': 1,
 'l': 1,
 'o': 1,
 'c': 1}

How to fix the appearance of unexpected characters in string counts

5 Answers5