recreation of absolute value finder not working as intended

Question

I have scripted a code that gives the absolute value of any number here is the code:

def absolute(num):
    numb = str(num)
    numb.replace("-","")
    numb = int(numb)
    return numb

When used it gives an output of the same integer:

>>> absolute(-12)
-12

When I did the function step by step I found out that there is the problem in int function where the string "12" gets converted into -12

I know other methods of making this but if you can explain why this happens and that would be better as I can understand what happens.

Thanks!

score 1 · Accepted Answer · answered Nov 27 '20 at 04:07

1

Here you don't assign .replace return value back to the variable:

def absolute(num):
    numb = str(num)
    numb = numb.replace("-","")
    numb = int(numb)
    return numb

In short:

def absolute(num):
    return int(str(num).replace('-',''))

And one bizarre thing, don't you know about abs() LOL?

abs(-12)

answered Nov 27 '20 at 04:07

Wasif

`numb = numb.replace`is a typo. I'll change it – POINT ONE Nov 27 '20 at 04:16
well I know about abs and I was just trying to recreate it – POINT ONE Dec 07 '20 at 03:13

score 0 · Answer 2 · answered Dec 03 '20 at 23:59

0

absolute = lambda x : int(str(x).replace('-',''))
absolute(-5)

I shortened the answer someone else gave you. Its a little slow when I time it but I'm sure it should work fine. :)

answered Dec 03 '20 at 23:59

sfdfsdfsdg

2 Answers2