Vs code regex replace part of string and keep other

Question

I need quick help with regex I have

'http://127.0.0.1:5000/register'

and want to replace it with

`${process.env.API_URL}/register`

doing this regex:

'http://127.0.0.1:5000/.*'

takes the whole thing

You don't need `.*`. Just replace `http://127.0.0.1:5000/` with `${process.env.API_URL}/` — Barmar, Nov 19 '20 at 08:30
Use a capture group to capture the variable part that matches `.*` and copy it to the replacement. — Barmar, Nov 19 '20 at 08:31

score 1 · Answer 1 · answered Nov 19 '20 at 08:33

1

Use a capture group to copy the part after /

Find: 'http://127.0.0.1:5000/(.*)'

Replace: `${process.env.API_URL}/$1`

answered Nov 19 '20 at 08:33

Barmar

1 Answers1